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Download Advanced Topics in Database Research, Vol. 1 by Keng Siau PDF

By Keng Siau

Complex themes in Database study positive factors the newest, state-of-the-art examine findings facing all features of database administration, structures research and layout and software program engineering. This e-book presents info that's instrumental within the development and improvement of thought and perform with regards to info know-how and administration of knowledge assets.

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1993) is a more recent benchmark than OO1 and HyperModel. It reuses their structures to propose a more complete benchmark and to simulate various transactions running on a diversified database. It has also been designed to be more generic than its predecessors and to correct their weaknesses in terms of object complexity and associative accesses. This is achieved with a rich schema and a comprehensive set of operations. Object-Oriented Database Benchmarks 39 However, if OO7 is a good benchmark for engineering applications, it is not for other types of applications such as financial, telecommunication, and multimedia applications (Tiwary, Narasayya, & Levy, 1995).

Binary) allow insertion of similar tuples. We should keep in mind that we are comparing the ability of the 28 Jones & Song Table 3: Lossless and FD preserving decompositions Case # Ternary Binary Impositions Potential Lossless Cardinality Decomposition (X:Y:Z) Potential FD Preserving Decompositions 1:1:1 (X:Y) = (M:1) (XY)(XZ) None 2 1:1:1 (X:Y) = (1:1) (XY)(XZ) -or(XY)(YZ) (XY)(XZ) -or(XY)(YZ) 3 1:1:1 (X:Y) = (M:1) (Z:Y) = (M:1) (XY)(XZ) -or(XZ)(ZY) (XY)(XZ) -or(XZ)(ZY) 4 1:1:1 (X:Y) = (M:1) (X:Z) = (1:1) (XY)(XZ) -or(XZ)(ZY) (XY)(XZ) -or(XZ)(ZY) 5 M:1:1 (X:Y) = (M:1) (XY)(XZ) (XY)(XZ) 6 M:1:1 (Y:Z) = (M:1) (XY)(YZ) None 7 M:1:1 (Y:Z) = (1:1) (XY)(YZ) -or(XZ)(ZY) (XY)(YZ) -or(XZ)(ZY) 8 M:1:1 (X:Y) = (M:1) (Y:Z) = (1:1) (XY)(YZ) -or(XZ)(ZY) -or(XY)(XZ) (XY)(YZ) -or(XZ)(ZY) 9 M:1:1 (X:Y) = (M:1) (Y:Z) = (1:M) (XZ)(ZY) -or(XY)(XZ) (XZ)(ZY) 10 M:N:1 (X:Z) = (M:1) (XY)(XZ) (XY)(XZ) 11 M:N:1 (X:Z) = (M:1) (Y:Z) = (M:1) (XY)(XZ) -or(XY)(YZ) None 12 M:N:P Not Allowed None None TE AM FL Y 1 structures to ensure enforcement of all constraints present (typically identified by the implicit functional dependencies).

Can we impose a binary relationship with cardinality M:1, between X and Y that are parts of a ternary relationship having 1:M:N (X:Y:Z) cardinality? The ternary relationship (1:M:N) can be minimally represented as follows: X1 : Y1 : Z1 X1 : Y1 : Z2 X1 : Y2 : Z1 Since this is a minimal representation of the 1:M:N cardinality, we can not remove any tuple. Note that the relationship X:Y is of cardinality 1:M; but the imposition of the binary requires that the relationship between X and Y be M:1. The binary imposition is therefore disallowed because the requirement for a single instance of Y for each instance of X has already been violated during construction of the ternary relationship.

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